If z + 1/z=2 cos theta , theta belongs to R. Show that |z|=1 and for any n belongs to Z, z^n + 1/z^n =2 cos n theta.
We note "|z|=r". With this notation the imaginary part of "z+1\/z" is "(r-1\/r) \\sin\\theta". Now as "2\\cos \\theta" is a real number, its imaginary part is zero. Therefore there are two cases :
Therefore, in any case we have "|z|=1" and so "z" can be written as "e^{i\\theta}". Using this expression we find that for any "n\\in \\mathbb{Z}" we have
"z^n + 1\/z^n = e^{in\\theta} + e^{-in\\theta}=2\\cos n\\theta"
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