Using the fact that if z = r(cosθ +isinθ) then z2 = r2(cosθ +isinθ), find the square root of
2√3 -2i
1
Expert's answer
2021-09-15T03:05:29-0400
Letz=23−2iargz=arctan(23−2)=−6π∣z∣=12+4=4⟹z=4e−6iπz21=±2e−12iπ=±2cos(12π)−(±i2sin(12π))=±2cos(12π)∓i2sin(12π)It implies that the square root is2cos(12π)−i2sin(12π)or−2cos(12π)+i2sin(12π)
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