Suppose π΄ is real 3 Γ 3 matrix that has the following eigenvalues and eigenvectors: β2, ( 1 1 1 ) , 1 + π, ( 1 β π 2 1 ) , 1 β π, ( 1 + π 2 1 ). Find a fundamental set of real valued solutions to π± β² = π΄π±.
Need an explanation as to how they got the following answer:
Answer: The first eigenvalue/eigenvector pair gives the solution π±π (π‘) = ( 1 1 1 ) π^ β2π‘ . The second eigenvalue/eigenvector pair gives the two solutions: π±π (π‘) = ( cos(π‘) + sin(π‘) 2 cos(π‘) cos(π‘) )π^ π‘ , π±π (π‘) = ( β cos(π‘) + sin(π‘) 2 sin(π‘) sin(π‘) )π^ t
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