Answer to Question #239901 in Geometry for 123

Question

given the points below, find xy. round to the nearest hundredth. x(-1,2) and y(4,0)

Answer 1

$xy=\sqrt{(4-(-1))^2+(0-2)^2}\\xy=\sqrt{(4+1)^2+(-2)^2}\\xy=\sqrt{(5)^2+(-2)^2}\\xy=\sqrt{25+4}$

$xy= \sqrt{29}=5.38516481$

hence

$xy=5.38$