Show that the dim R5=5
If U is a subspace of W then
D1: dim U ≤ dim W, and
D2: if dim U = dim W then U = W
Proof: Let "u_1.....u_k" be a basis for U.
By Superset-Basis Lemma, there is a basis B for W that contains "u_1.....u_k"
"B = \\{u_1...u_k;b_1...b_r\\} \\\\\nThus \\space k \u2264 |B|, and\\\\\nIf \\space k = |B| \\space then \\{u_1...u_k\\} = B"
This implies that RB=B
So, R5=5
Comments
Leave a comment