Find a basis and the dimension of the subspace W of ℝ^3 where W = {( x, y, z ) ∈ ℝ^3 ∶ x + y + z = 0 }.
From the equality "x+y+z=0" we find that "z=-(x+y)". Thus, the space is 2-dimensional. To find the basis we set: "x_1=1,y_1=0" and "x_1=0,y_1=1". We receive vectors: "(1,0,-1)" and "(0,1,-1)". This is the basis of "W."
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