A company produces two types of presentation goods A and B that requires gold and sliver. Each unit of type A requires 3 g of sliver and 1g of gold while B requires 1 g of sliver and 2 g of gold. The company can produce 9 g of sliver and 8 g of gold. Each unit of type A brings a profit of RS 40 and that type B a profit of Rs 50, determine the number of units of each type that should be produced in order to maximize profit.
We have that type A requires 3g of silver and 1g of gold and type B requires 1g of silver and 2g of gold.
Silver is 9g, gold is 8g.
Let type A be x and type B be y. Therefore we have
"3x+y\\le9"
"x+2y\\le8"
"x\\ge0, y\\ge0"
Type A gives profit 40Rs and type B gives profit 50Rs. Thus
"40x+50y= z" (max this profit)
Solving for two inequalities:
"3x+y\\le9"
"x+2y\\le8 \\implies x\\le2 \\ and\\ y\\le3"
Thus max profit would be: "40\\cdot2+50\\cdot3=230"
Answer: 230
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