The owner of a restaurant that serves continental food wants to study characteristics of his customers. He decides to focus on two variables: the amount of money spent by customers and whether customers order dessert. The results from a sample of 60 customers are as follows: • Amount spent: X=$38.54, S= $7.26 • 18 customers purchased dessert. a. Construct a 95% confidence interval estimate of the population mean amount spent per customer in the restaurant.
Confidence interval:
"\\=x\\pm z\\frac{s}{\\sqrt{n}}"
z is the chosen Z-value (1.96 for 95% from t-table)
"38.54-(1.96)(\\frac{7.26}{\\sqrt{60}})<\\mu<38.54+(1.96)(\\frac{7.26}{\\sqrt{60}})"
"36.70<\\mu<40.38"
95% confidence interval is (36.70, 40.38)
Comments
Leave a comment