Answer to Question #224814 in Classical Mechanics for John Enefiok Usoro

Question

40×4g×40^3=bw^3E............(1)
60×4g×60^3=bw^3E............(2)
Solve for E and g simultaneously

Answer 1

There is no solution:

$$\frac{40\cdot4g\cdot40^3}{60\cdot4g\cdot60^3}=\frac{32}{81}\\ \frac{bw^3E}{bw^3E}=1$$