Answer to Question #298349 in Electricity and Magnetism for lomon11111

Question

Two-point charges are arranged on the x-y coordinate system as follows: q1= 4x10^-8 C at (0,3 m) and q2= -9x10^-7 C at (5,0 m). Find the electric origin at (0,0). Using the Pythagorean theorem calculate for the magnitude E of the resultant electric field.

Answer 1

Answer

Electric field at origin due to q₁

$E_1=\frac{kq_1}{r^2}\\=\frac{9*10^9*4*10^{-8}}{3^2}\\=40N/C$

Electric field at origin due to q₂

$E_2=\frac{kq_2}{r^2}\\=\frac{9*10^9*9*10^{-7}}{5^2}\\=324N/C$

So net electric field at origin is $E=\sqrt{E_1^2+E_2^2}\\=\sqrt{(40)^2+(324)^2}\\=326.46N/C$