Answer to Question #298365 in Electricity and Magnetism for samantha

Question

Two equal positive charges q1 = q2 = 4.0 μC are located at x = 0, y = 0.30 m, x = 0, y = -0.30 m and respectively. What are the magnitude and direction of the total electric force that q1 and q2 exert on a third charge at Q = 4.0 μC x = 0.40 m, y = 0?

Answer 1

Answer

Force on third charge Q is only horizontal components addition and vertical cancelled out.

$F=2*\frac{kq_1q_2}{r^2}\\=\frac{2*16*10^{-12}}{0.5}\\=64**10^{-12}N$