Answer to Question #126403 in Field Theory for ameerat

Question

A spring of force constant 1500N/m is acted upon by a force of 75N. Calculate the potential energy stored in the spring

Answer 1

Since,

$$F=kx$$

Thus,

$$75=1500x\implies x=5\times10^{-2}m$$

And potential energy is

$$U=\frac{1}{2}kx^2\\\implies U=1.875J$$