Answer to Question #291845 in Mechanics | Relativity for bookaddict

Question

a child of mass 40 kg slides down a water slide that is 15 m high. at the bottom her velocity is 9.7 m/s. approximately how much energy was "lost" due to friction?

Answer 1

Solution

Mass of child m=40kg

Height h=15m

Velocity at bottom

v=9.7m/s

So energy at height h

U=mgh

=$40\times9.81\times15$

$=5886J$

Energy at bottom

E=$0.5mv^2$

$=0.5\times40\times(9.7) ^2\\=1881.8J$

Loss of energy due to friction

$=U-E\\=5886-1881.8\\=4004.2J$