Let B = 5.30 m
at 60.0°. C
and A
have equal magnitudes. The direction angle of C
is larger than that of A
by 25.0°. Let A · B = 27.0 m2
and B · C = 34.5 m2.
Find the magnitude (in m) and direction (in degrees) of A.
Let θ represent the angle between A and B. Turning by 25.0° makes the dot product larger, so the angle between C and B must be smaller.
We call it θ−25.0°. Then we have 5Acosθ=30 and 5Acos(θ−25.00)=35.
Then Acosθ=6 and A(cosθcos25.0+sinθsin25.0°)=7.
Dividing,
cos25.0°
+tanθsin25.0°=7/6
or tanθ=(7/6−cos25.0°)/sin25.0°
=0.616.
Which gives θ=31.6°.
Then the direction angle of A is
60.0°−31.6°=28.4°.
Substituting back,
Acos31.6°=6, so A=7.05 m at 28.4°.
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