Air is compressed in a diesel engine from an initial pressure of 13 psia and a temperature of 120 F to one-twelfth of its original volume. Calculate the final temperature assuming the compression is adiabatic
"P_1 = 13 \\; psia \\\\\n\nT_1 = 120 \\; \u00b0F = 322.039 \\; K \\\\\n\nV_2 = \\frac{V_1}{12}"
Adiabatic compression
"\\frac{P_2}{P_1} = (\\frac{V_1}{V_2})^\u03b3 \\\\\n\n\\frac{T_2}{T_1} = (\\frac{V_1}{V_2})^{\u03b3-1} \\\\\n\nP_2 = P_1 \\times (12)^{1.4} \\\\\n\n= 13 \\times (12)^{1.4} \\\\\n\nP_2 = 421.499 \\; psia \\\\\n\nT_2 = T_1 \\times (\\frac{V_1}{V_2})^{\u03b3-1} \\\\\n\n= 322.039 \\times (12)^{0.4} \\\\\n\n= 870.123 \\; K \\\\\n\nT_2 = 1106.551 \\; \u00b0F \u2248 1010 \\; \u00b0F"
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