A converging lens of focal length 0.40cm is combined with a diverging lens of focal length 0.20cm the power of combination of the lens is
Focal length of the converging lens is 0.40 cm i.e. f1 = 0.004 m
Focal length of the diverging lens is 0.20 cm i.e. f2 = −0.002 m
"P=\\frac{1}{f}=\\frac{1}{f_1}+\\frac{1}{f_2}=\\frac{1}{0.004}+\\frac{1}{-0.002}=-250" D
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