A beam of vertically polarized linear light is perpendicularly incident on an ideal linear polarizer. Show that if its transmission axis makes an angle of 60° with the vertical only 25% of the irradiance will be transmitted by the polarizer.
Let the irradiance of beam of polarized light be "I(0)" then,
According to Malus Law,
where "\\theta" = angle between direction of polarized light and transmission axis
Here "\\theta" = "{60}\\degree"
"I(\\theta)=" Irradiance of polarized light after emerging from ideal linear polarizer
On substituting the value of "\\theta" = "{60}\\degree" in equation (i) we get,
Hence, 25% of the irradiance will be transmitted by the polarizer if transmission axis makes an angle of 60° with the vertical .
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