Answer to Question #334272 in Physics for bela

Question

A pool ball leaves a 0.60-meter high table with an initial velocity of 2.4 m/s. Predict the time required for the pool ball to fall to the ground and the horizontal distance between the table's edge and the ball's landing location.

Answer 1

The time required for the pool ball to fall to the ground

$$t=\sqrt{2H/g}\\ =\sqrt{2*0.60/9.8}=0.35\:\rm s$$

The horizontal distance between the table's edge and the ball's landing location

$$L=v_0t=2.4*0.35=0.84\:\rm m$$