Answer to Question #348286 in Analytic Geometry for Kalai

Question #348286

Show that the centre of all sections of the sphere x² + y ² +z² = r² by the planes through a point (a,b,c) lie on the sphere x(x-a)+y(y-b)+z(z-c)=0

1
Expert's answer
2022-06-07T14:51:54-0400

All sections of the sphere x² + y ² +z² = r² by the planes through a point (a,b,c) is poin (0, 0, 0), which lies on the sphere x(x-a)+y(y-b)+z(z-c)=0.


Check:

0*(0-a) + 0*(0-b) + 0*(0-c) = 0 + 0 + 0 = 0


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