Answer to Question #308860 in Field Theory for Ara

Question

An average human weights about 650 N.if two such generic humans each carried 1.0 coulomb of excess charge,one positive and one negative. How far apart would they have to be for the electric attraction between them to equal their 650-N weight

Answer 1

Answer

So the distance is given by

$R=\sqrt{\frac{kqq'}{F}}\\=\sqrt{\frac{9*1*1}{650}}\\=11.74cm$