Answer to Question #325173 in Physical Chemistry for jec

Question

NH3+O2=NO+H2O IF 25G NH3 is reacted with 20g O2, which is the limiting reagent? How much NO will be formed in the reaction?

Answer 1

m(NH₃) = 25 g;

M(NH₃) = 17 g/mol;

n(NH₃) = m(NH₃)/M(NH₃) = 25/17 = 1.471 mol;

m(O₂) = 20 g;

M(O₂) = 32 g/mol;

n(O₂) = m(O₂)/M(O₂) = 20/32 = 0.625 mol;

4NH₃ + 5O₂ = 4NO + 6H₂O

By the chemical reaction:

n(NH₃)' = n(NH₃)/4 = 0.368 mol;

n(O₂)' = n(O₂)/5 = 0.625/5 = 0.125 mol;

So, O₂ is the limiting reagent and NH₃ is the excess reagent.

n(NO) = 4/5 * n(O₂) = 4/5 * 0.625 = 0.5 mol;

M(NO) = 30 g/mol;

m(NO) = n(NO) * M(NO) = 0.5 * 30 = 15.0 g.

Answer: 15.0 g