π (π) (π§) = π! /2ππ β«ππ· π(π€)ππ€ / (π€βπ§)π+1 . using the generalized Cauchy integral formula (GCIF) expressed in
Prove it with the Mathematical Induction Method.(As is known, the formula for = 1 is Cauchy Integral
It becomes the Cauchy Integral Formula (CIF), which is the result of the theorem and it is correct.)
Show that
a)z+z*=2 Re z=2x
b)z-z*=2i Im z=2iy
c)z/z*={x^2-y^2/x^2+y^2}+i{2xy/x^2+y^2}
Β π΄ = { π§ β β:|π§| < 1 π£π |π§ β 1/ 2 | > 1 /2 } βͺ { 1/ 2 } denote the set in the complex plane and
π΄ β² and ππ΄ = π΄Μ \ π΄π
Write the set.
Let f(z) = sin z/z
and f(0) = 0. Explain why f is analytic at z = 0. Find the MaclaurianΒ
series for f(z) and g(z) = β« f(ΞΎ)dΞΎ from 0 to z
. Does there exist a function f with anΒ
isolated singularity at 0 and such that |f(z)|~ exp( 1/|z|) near z= 0?Β