Answer to Question #324539 in Linear Algebra for Busi

Question #324539

Find a polynomial, P(x), of degree 3 with zeros of 4,1 and −1, if P(0) = 8

Expert's answer

"P(x)=a(x-4)(x-1)(x+1)".

"P(0)=8 \\to a(-4)(-1)*1=8 \\to a=2."

"P(x)=2(x-4)(x-1)(x+1)=2x^3-8x^2-2x+8."

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