Since X converges to π₯ β 0 0 there exists πΎ such that for all π > πΎ: π₯n β 0
Let πππ ππ = π§.
π converges to π₯ for all π greater than a certain number and ππ converges to π§
for all π greater than some number.
Since π = "\\frac{XY}{X}" ππ π β 0, by properties of limits, π converges to "\\frac zx" .
Hence π is convergent .
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