Answer to Question #173776 in Trigonometry for Jon jay Mendoza

Question

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1.f(x)=2 sin (x-​π/​4)

2.f(x)=sin (x+π/​3)

3.f(x)=3 cos (x+π/​6)

4.f(x)=2 cos (x-2π)

5.f(x)=tan x

Answer 1

1.f(x)=2 sin (x-​π/​4)

Solution: x-​π/​4=​πk, k€Z
x=​π/​4+​πk, k€Z

2.f(x)=sin (x+π/​3)

Solution :x+π/​3=​πk, k€Z
x=-π/​3+​πk, k€Z

3.f(x)=3 cos (x+π/​6)

Solution: x+π/​6=π/​2+​πk, k€Z
x=-π/​6+π/​2+​πk, k€Z
x=π/​3+​πk, k€Z

4.f(x)=2 cos (x-2π)

Solution:cos(x-2π)=cos(x) 
x=π/​2+​πk, k€Z

5.f(x)=tan x

Solution: x=πk, k€Z